Adding, Subtracting and Multiplying Complex Numbers
Addition and subtraction of complex numbers are performed as if the complex
numbers were algebraic expressions with i being a variable.
Example 1
Addition and subtraction of complex numbers
Find the sums and differences.
a) (2 + 3i) + (6 + i)
b) (-2 + 3i) + (-2 - 5i )
c) (3 + 5i) - (1 + 2i)
d) (-2 - 3i) - (1 - i )
Solution
a) (2 + 3i) + (6 + i) = 8 + 4i
b) (-2 + 3i) + (-2 - 5i ) = -4 - 2i
c) (3 + 5i) - (1 + 2i) = 2 + 3i
d) (-2 - 3i) - (1 - i ) = -3 -2i
We can give a symbolic definition of addition and subtraction as follows.
Addition and Subtraction of Complex Numbers
The sum and difference of a + bi and c + di are defined as follows:
(a + bi) + (c + di) = (a + c) + (b + d)i
(a + bi) - (c + di) = (a - c) + (b - d)i
Complex numbers are multiplied as if they were algebraic expressions. Whenever
i2 appears, we replace it by -1.
Example 2
Products of complex numbers
Find each product.
a) 2i(1 + i)
b) (2 + 3i)(4 + 5i)
c) (3 + i)(3 - i)
Solution
a) 2i(1 + i) |
= 2i + 2i2 |
Distributive property |
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= 2i + 2(-1) |
i2 = -1 |
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= -2 + 2i |
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b) Use the FOIL method to find the product:
(2 + 3i)(4 + 5i) |
= 8 +10i + 12i + 15i2 |
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= 8 + 22i + 15(-1) |
Replace i2 by -1. |
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= 8 + 22i - 15 |
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= -7 + 22i |
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c) This product is the product of a sum and a difference.
(3 + i)(3 - i) |
= 9 - 3i + 3i - i2 |
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= 9 - (-1) |
i2 = -1 |
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= 10 |
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We can find powers of i using the fact that i2 = -1. For example,
i3 = i2 · i = -1 · i = -i.
The value of i4 is found from the value of i3:
i4 = i3 · i = -i · i = -i2 = 1.
In the next example we find more powers of imaginary numbers.
Example 3
Powers of imaginary numbers
Write each expression in the form a + bi.
a) (2i)2
b) (-2i)2
c) i6
Solution
a) (2i)2 = 22 · i2 = 4(-1) = -4
b) (2i)2 (2)2 i2 4i2 4(1) 4
c) i6 = i2 · i4 = -1 · 1 = -1
For completeness we give the following symbolic definition of multiplication of
complex numbers. However, it is simpler to find products as we did in Examples 2
and 3 than to use this definition.
Multiplication of Complex Numbers
The complex numbers a + bi and c + di are multiplied as follows:
(a + bi)(c + di) = (ac - bd) + (ad + bc)i
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